Systems of Equations: Linear and Nonlinear
Advanced PSAT Math includes systems involving one linear and one quadratic equation. To solve: express the linear equation as y = mx + b, substitute into the quadratic, and solve the resulting quadratic. The discriminant of the resulting equation tells you how many intersection points exist: two intersections (discriminant > 0), one intersection (tangent, discriminant = 0), no real intersections (discriminant < 0). Example: y = 2x + 3 and y = xΒ² β 2. Substitute: xΒ² β 2 = 2x + 3 β xΒ² β 2x β 5 = 0. Discriminant: 4 + 20 = 24 > 0, so two intersection points. PSAT questions may present the system in graphical form and ask for the number of solutions β recognize that a line tangent to a parabola means exactly one solution.